WebApr 25, 2024 · What is the second derivative of x2 sin x? Calculus Basic Differentiation Rules Product Rule 1 Answer 1s2s2p Apr 25, 2024 d2y dx2 = 2sinx +4xcosx −x2sinx Explanation: We have y = x2sinx dy dx = d dx [x2]sinx + x2 d dx [sinx] = 2xsinx + x2cosx WebMay 22, 2016 · In x2sinx, we have two functions: x2 and sinx. Since they are being multiplied together, we'll need to use the product rule to find the derivative. Let u = x2 …
Derivative of Sin Square x Sin^2x Derivative - Mathstoon
WebCalculus. Derivative Calculator. Step 1: Enter the function you want to find the derivative of in the editor. The Derivative Calculator supports solving first, second...., fourth … Weband multiplying by x 2 gives: x 2 sin ( x 2) = ∑ n = 0 ∞ ( − 1) n ( 2 n + 1)! x 4 n + 4. Now if we want to antidifferentiate this quantity we find: ∫ x 2 sin ( x 2) d x = C + ∑ n = 0 ∞ ( − 1) n ( 4 n + 5) ( 2 n + 1)! x 4 n + 5. Share Cite Follow answered Apr 12, 2016 at 17:15 Joel 16k 1 31 47 Add a comment 0 Fresnel's integrals are defined as: netter\u0027s atlas of human anatomy 5th edition
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WebJun 21, 2024 · Technically x 2 sin ( 1 / x) is undefined at x = 0. You can define f ( x) = x 2 sin ( 1 / x) and set f ( 0) = 0 to make f differentiable everywhere, but differentiating f using the formula f ( x) = x 2 sin ( 1 / x) doesn't tell you what is f ′ ( 0) because the formula is not applicable there. – Qiyu Wen Jun 21, 2024 at 9:34 WebApr 25, 2024 · What is the second derivative of x2 sin x? Calculus Basic Differentiation Rules Product Rule 1 Answer 1s2s2p Apr 25, 2024 d2y dx2 = 2sinx +4xcosx −x2sinx … WebDifferentiate the function w.r.t. x. x x−2 sinx Medium Solution Verified by Toppr Let y=x x−2 sinx Also, let x x=u and 2 sinx=v ∴y=u−v ⇒ dxdy= dxdu− dxdv u=x x Taking logarithm on both the sides, we obtain logu=xlogx Differentiating both sides with respect to x, we obtain u1dxdu=[dxd (x)×logx+x× dxd (logx)] ⇒ dxdu=u[1×logx+x× x1] ⇒ dxdu=x x(1+logx) netter\u0027s atlas of anatomy