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WebRS Aggarwal Solutions for Class 12 Maths Chapter 11 – Applications of Derivatives Hence, A is least when side of square is equal to the diameter of the circle. 12. Show that the right triangle of maximum area that can be inscribed in a circle is an isosceles triangle. Solution: We know that AC = 2r cos θ AB = 2r sin θ It can be written as WebRS Aggarwal Solutions for Class 12 Maths Chapter 13 – Methods of Integration = - x cot x + ∫ cot x dx Again by integration we get = - x cot x + log sin x + c 8. ∫ x2 cos x dx Solution: It is given that ∫ x2 cos x dx We can write it as By integrating w.r.t x = x2 sin x - ∫ 2x sin x dx So we get = x2 sin x – 2 [∫ x sin x dx] fond salesforce
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