2024 The emf of the following cells are ag/ag+

The emf of the following cells are ag/ag+

Author: gkym

August undefined, 2024

WebCalculate the emf of the following cell at 25∘C : Ag(s) Ag+(10−3M) Cu2+(10−1M) Cu(s) Given E∘ cell = +0.46 V and log 10n = n. Solution For the given cell, the redox reaction is … WebExplain the following: (i) Nernst Equation. (ii) Aqua regia. Hard. View solution > How does cell EMF depend on increasing the concentration of KOH ? Hard. View solution > How will concentration of Zn 2 + ions and Ag + ions be affected when the cell functions? Hard. View solution > How will the concentration of Zn 2 + ions and Ag + ions be ...

The emf of the cell, Ag /Ag^+ (0.1 M) / /Ag at 298 K is (a) …

WebApr 28, 2013 · calculate the standard emf of a cell which involves the following cell reaction.Zn + 2Ag+ ->Zn(+2) +2Ag.given that Eocell of zinc= 0.76V,Eocell of Ag= -0.80V. Asked by FIZA SINGH 28 Apr, 2013, 01:08: PM Expert Answer Answered by 29 Apr, 2013, 10:27: AM Concept Videos. This video explains comparison and calculation of … WebJun 29, 2024 · Where, Ecell = the EMF of the cell, Eo = Standard EMF of cell, [ Mg2+ ] = Concentration of Mg, [ Ag+] = Concentration of Ag, n = ion charge ( moles of electrons ). We can given that, The EMF of the cell is = 2.96 V, Concentration of Mg [ Mg2+ ] = 0.130 M . Concentration of Ag [ Ag+ ] = 1.0 x 10-4 M. We can write the Cell reaction as, Mg + 2 Ag+ ... camelot golfland address

Consider the cell Cu/Cu^+2 Ag^+/Ag.If the concentration of Cu^+2 and

WebA voltaic cell utilizes the following reaction: Al (s) + 3Ag+ (aq) Al3+ (aq) + 3Ag (s) What is the effect on the cell emf of each of the following changes? A Water is added to the anode compartment, diluting the solution. (a)The cell emf will increase. (b)The cell emf will decrease. (c)The cell emf will remain the same. WebIn which of the following cases blood cells will shrink: (a)when placed in water containing more than 0.9% (mass/ volume) NaCl ... E°Ag+/Ag= 0.8 0 v) 5. A copper-silver cell is set up. The copper ion concentration is 0.10 M. The ... What is the emf a cell when the cell reaction attains equilibrium? WebThe EMF of the Daniell cell is 1.1V . The external EMF to be applied for the following reaction to take place in it is: C u ( s ) + Z n ( a q ) 2 + → C u ( a q ) 2 + + Z n ( s ) camelot group address

CBSE Class 12-science Answered - TopperLearning

Consider the cell Cu/Cu^+2 Ag^+/Ag.If the concentration of

WebE) Electrolytic cells are cells where electron flow is caused by spontaneous reactions. Answer: E Reference: Section 20-1 8) Choose the correct statement based on the following oxidation potentials. Mg/Mg2+ +2.37 v Fe/Fe2+ +0.44 v Cu/Cu2+ -0.34 v Zn/Zn2+ +0.76 v Sn/Sn2+ +0.14 v Ag/Ag+ -0.80 v A) Mg will not displace Zn2+ from solution Webসঠিক উত্তর : a এবং b উভয়ই অপশন ১ : cuo+h2=cu+h2o অপশন ২ : feo+co=fe+co2 অপশন ৩ : h2s+ci2=s+2hci অপশন ৪ : a এবং b উভয়ই coffee mate chocolate chip cookie creamerWebThe emf (E^∘) of the following cells are: Ag/ Ag^+ (1 M)∥ Cu^2 + (1 M) Cu; E^∘ = - 0.46 volt Zn/Zn^2 + (1 M) ∥ Cu^2 + (1 M) Cu; E^∘ = + 1.10 volt Calculate the emf of the cell: Zn Zn^2 + (1 M)∥ Ag^+ (1 M) Ag . Class 12. >> Chemistry. >> Electrochemistry. >> Nernst Equation. coffee mate cartridge

"WebJun 4, 2014 · Write the Nernst equation and calculate the emf of the following cell at 298 K.Cu (s) Cu 2+ (0.130 M) Ag + (1.00M) Ag (s) Given: E o Cu2+/Cu = 0.34V and E o Ag+/Ag = +0.80 V. Asked by Topperlearning User 04 Jun, 2014, 01:23: PM Expert Answer Answered by 04 Jun, 2014, 03:23: PM Concept Videos ... " - The emf of the following cells are ag/ag+

The emf of the following cells are ag/ag+

3.30 Consider a cell composed of the following two half cells

WebThe emf of the following cells are: A g A g + (1 M) C u 2 + (1 M) C u E c e l l = − 0.46 V a n d Z n Z n 2 + (1 M) C u 2 + (1 M) C u E c e l l = + 1.10 V. Then the emf of the cell Z n … WebCalculate the emf of the following cell at 25∘ C : Ag s Ag +10 3 M Cu 2+10 1 M Cu s Given Ecell ∘=+0.46 V and log 10 n = n. Login. Study Materials. NCERT Solutions. NCERT Solutions For Class 12. ... Q. Calculate the emf of the following cell at 25 o C A g (s) ...

Did you know?

WebFigure 11.2.3: A galvanic cell can be used to determine the standard reduction potential of Ag +. The SHE on the left is the anode and assigned a standard reduction potential of zero. Table 11.2.1: Selected Standard Reduction Potentials at 25 °C. Half-Reaction. E° (V) F 2(g) + 2e − 2F − (aq) +2.866. WebThe emf of the following cells are:Ag Ag +1 M Cu 2+1 M Cu E cell = 0.46 V andZn Zn 2+1 M Cu 2+1 M Cu E cell =+1.10 VThen the emf of the cell Zn Zn 2+1 M Ag +1 M Ag is:A. 0.64 VB. 1.1 VC. 1.56 VD. 0.64 V. Login. Study Materials. NCERT …

WebStudy with Quizlet and memorize flashcards containing terms like Electrolytic cells utilize electrical energy to drive non-spontaneous redox reactions. (true/false), Which one of the following is not a redox reaction?, Consider the following redox equation Mn(OH)2(s) + MnO4-(aq) ® MnO42-(aq) (basic solution) When the equation is balanced with smallest … WebStart your trial now! First week only $4.99! arrow_forward Literature guides Concept explainers Writing guide Popular textbooks Popular high school textbooks Popular Q&A Business Accounting Business Law Economics Finance Leadership Management Marketing Operations Management Engineering AI and Machine Learning Bioengineering Chemical …

WebE.m.f of the following cell at 298 K in V is x×10 2.Zn Zn2+ 0.1 M Ag+0.01 M AgThe value of x is . ... 0ex0exEAg+/Ag° =+0.80 V ; 0ex0ex2.303 RT/F = 0.059. Login. Study Materials. NCERT Solutions. NCERT Solutions For Class 12. NCERT Solutions For Class 12 Physics; NCERT Solutions For Class 12 Chemistry; NCERT Solutions For Class 12 Biology ... WebJul 16, 2024 · $\begingroup$ @DivMit $$\ce{Ag+(aq) + e- <=> Ag(s)}$$ is a balanced half reaction, and if it describes both half-cells, you get the chemical equation you have in your comment. The concentration of silver cations in the two half cells indirectly depends on the concentration of chloride or bromide (as you can see in the calculation).

WebThe EMF of the cell Zn∣Zn 2+(1M)∣∣Ag +(1M)∣Ag will be: A 1.56 V B 0.64 V C -1.56 V D 2.02 V Medium Solution Verified by Toppr Correct option is A) Cu+2Ag +→2Ag+Cu +2 E …

WebThe standard potential of Ag/Ag+half cell is +0.80 V and Zn/Zn2+ is -0.76 V. Q3.What is the Emf of the following cell at 25 0 C. Zn 2+ /Zn(0.2M) //Ag+(0.002 M)/Ag(s) coffee mate chocolate chip creamerWebCalculate the emf of the concentration cell at 298 K. Ag / Ag+ (0.002 M) // Ag+ (0.5 M)/Ag. What will be the potential of above cell, when the. concentration silver ions is changed from 0.002 M to 0.005 M at the same coffee mate cinnamon creamerWebDec 10, 2024 · From the table of standard reduction potentials, you find (3) Li + + e − → Li E ∘ = − 3.045 (4) Ag → Ag + + e − E ∗ = − 0.799 According to the convention of the cell, the … coffee mate chocolate creamer powderWebOct 27, 2024 · Calculate the EMF of the concentration cell at 298 K: Ag/Ag^+ (0.005 M)//Ag^+ (0.5 M)/Ag. coffeemate coffee creamer - 450g coffee mate class actionWebNov 2, 2024 · A voltaic cell is setup at 25°C with the half cells Ag+ (0.001 M) Ag and Cu2+ (0.10 M) Cu. What should ... potential ? [E° = 0.46 V, log 105 = 5] LIVE Course for free. Rated by 1 million+ students ... Calculate the emf of the following cell at 25°C : asked Nov 2, 2024 in Chemistry by Richa (61.0k points) electro chemistry; redox reaction ... camelot golfland waterslidesWebGiven E Ag+ / Ag = + 0.8 V, ENi +2 / Ni = – 0.25 V. Which of the following statements is true ? (A) Ag+ is an oxidizing agent but Ni+2 is a reducing agent (B) Ni+2 can be reduced by silver metal (C) Ag+ is a better oxidizing agent than Ni+2 and Ni is a better reducing agent than Ag. coffee mate chocolate creme powder